Issue
There is a fun method0:
private fun method0() {
println("method0 fun")
}
And a var method0 :
var method0 = {
println("method0")
}
It seems they are used the same:
method0()
I found that both occur at the same time, and the fun function has a higher priority when the code calls.
Other than that, is there any difference between them?
Solution
The var
way of doing it results in a functional object. The lambda content is wrapped as a functional object so it can be passed around like any other instance of a class. It can directly be used as a function parameter, for instance.
var method0 = {
println("method0")
}
fun doSomethingTwice(action: ()->Unit) {
repeat(2) { action() }
}
fun main() {
doSomethingTwice(method0)
}
And since it’s marked as a var
you can swap it out for a different function:
fun main() {
method0 = { println("hello, world!") }
doSomethingTwice(method0)
}
Note that this way of specifying a function is a little bit heavier since it is wrapping the function in another class instance.
And you can still wrap any "regular" function into a functional object at any time by using ::
to avoid doing it until it’s necessary.
fun method0() {
println("method0")
}
fun main() {
doSomethingTwice(::method0)
}
Answered By – Tenfour04
Answer Checked By – Clifford M. (BugsFixing Volunteer)