[SOLVED] Very simple function gives no output ( Python 3.7)

Issue

First-Timer here 🙂

The very simple function geome(x) gives no output, eventhough the exact same code works fine outside of the function (see "z = list …").

What am I doing wrong?

Would very much appreciate some help or hintsThank you.

from operator import truediv

x = [1, 2, 4, 8, 16]

z = list(map(truediv, x[1:], x[:-1])) # This Works perfectly fine! >>> Geometric
if all(num == z[0] for num in z):
    print('Geometric')


def geome(x):
    z = list(map(truediv, x[1:], x[:-1])) 
    if all(num == x[0] for num in z):
        print('Geometric')

geome(x) # Doesn't work, even though it is the same code as above, only inside of a function. >>> 

Solution

Your geome implements something different to what you have outside. In the if clause you changed z[0] to x[0], so geome should be like this instead:

def geome(x):
    z = list(map(truediv, x[1:], x[:-1])) 
    if all(num == z[0] for num in z):
        print('Geometric')

Answered By – molinav

Answer Checked By – Clifford M. (BugsFixing Volunteer)

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