## Issue

i tray to build function to show the high and lowest number but between 0 and 20

```
"use strict";
let scors = [50, 70, 60, 20, 15, 14, 12, 10, 9, 8, -5, 4, 16, 2, 17.5, 12.75];
function minMax(score) {
let max = score[0];
let min = score[0];
for (let i = 0; i < score.length; i++) {
if (score[i] < min && score[i] >= 0) {
min = score[i];
}
//this part dose not work
if (score[i] > max && score[i] <= 20) {
max = score[i];
}
}
console.log(max);
console.log(min);
}
minMax(scors);
```

## Solution

These are the conditions you applied, the **current score** must be greater than `max`

and less than `20`

.

```
if (score[i] > max && score[i] <= 20) {
max = score[i];
}
```

This is an example of 4th first iteration.

- Iteration 1:
`input: 50`

>`max: 50`

- Iteration 2:
`input: 70`

>`max: 50`

- Iteration 3:
`input: 60`

>`max = 50`

- Iteration 4:
`input: 20`

>`max = 50`

In the 4th iteration, the

`max`

is not assigned as`20`

because it doesn’t greater than thecurrent maxwhich is 50.

Here is the simple solution:

- Add
`score.sort();`

for sorting the array before start looping. - Define the
`min`

with the last index of the array.

```
'use strict';
let scors = [50, 70, 60, 20, 15, 14, 12, 10, 9, 8, -5, 4, 16, 2, 17.5, 12.75];
function minMax(score) {
score.sort();
let max = score[0];
let min = score[score.length - 1];
for (let i = 0; i < score.length; i++) {
if (score[i] < min && score[i] >= 0) {
min = score[i];
}
// This part now works!
if (score[i] > max && score[i] <= 20) {
max = score[i];
}
}
console.log(max);
console.log(min);
}
minMax(scors);
```

Answered By – amlxv

Answer Checked By – Terry (BugsFixing Volunteer)