I have this table for documents (simplified version here):
How do I select one row per id and only the greatest rev?
With the above data, the result should contain two rows:
[1, 3, ...] and
[2, 1, ..]. I’m using MySQL.
Currently I use checks in the
while loop to detect and over-write old revs from the resultset. But is this the only method to achieve the result? Isn’t there a SQL solution?
At first glance…
All you need is a
GROUP BY clause with the
MAX aggregate function:
SELECT id, MAX(rev) FROM YourTable GROUP BY id
It’s never that simple, is it?
I just noticed you need the
content column as well.
This is a very common question in SQL: find the whole data for the row with some max value in a column per some group identifier. I heard that a lot during my career. Actually, it was one the questions I answered in my current job’s technical interview.
It is, actually, so common that Stack Overflow community has created a single tag just to deal with questions like that: greatest-n-per-group.
Basically, you have two approaches to solve that problem:
Joining with simple
group-identifier, max-value-in-group Sub-query
In this approach, you first find the
group-identifier, max-value-in-group (already solved above) in a sub-query. Then you join your table to the sub-query with equality on both
SELECT a.id, a.rev, a.contents FROM YourTable a INNER JOIN ( SELECT id, MAX(rev) rev FROM YourTable GROUP BY id ) b ON a.id = b.id AND a.rev = b.rev
Left Joining with self, tweaking join conditions and filters
In this approach, you left join the table with itself. Equality goes in the
group-identifier. Then, 2 smart moves:
- The second join condition is having left side value less than right value
- When you do step 1, the row(s) that actually have the max value will have
NULLin the right side (it’s a
LEFT JOIN, remember?). Then, we filter the joined result, showing only the rows where the right side is
So you end up with:
SELECT a.* FROM YourTable a LEFT OUTER JOIN YourTable b ON a.id = b.id AND a.rev < b.rev WHERE b.id IS NULL;
Both approaches bring the exact same result.
If you have two rows with
group-identifier, both rows will be in the result in both approaches.
Both approaches are SQL ANSI compatible, thus, will work with your favorite RDBMS, regardless of its "flavor".
Both approaches are also performance friendly, however your mileage may vary (RDBMS, DB Structure, Indexes, etc.). So when you pick one approach over the other, benchmark. And make sure you pick the one which make most of sense to you.
Answered By – Adriano Carneiro
Answer Checked By – Clifford M. (BugsFixing Volunteer)