[SOLVED] Set custom UIView frame in UIViewRepresentable SwiftUI

Issue

I’m trying to use my custom UIView in SwiftUI using UIViewRepresentable and I want my UIView to have the same size as I set in .frame() so that I can use it like this:

MyViewRepresentable()
.frame(width: 400, height: 250, alignment: .center)

For example, I can set a frame as a property:

struct MyViewRepresentable: UIViewRepresentable {
    var frame: CGRect
    func makeUIView(context: Context) -> UIView {
        let myView = MyView(frame: frame)

        return view
    }
    func updateUIView(_ uiView: UIView, context: Context) {}
}

Usage:

struct ContentView: View {
    var body: some View {
        MyViewRepresentable(frame: CGRect(x: 0, y: 0, width: 400, height: 250))
            .frame(width: 400, height: 250, alignment: .center)
    }
}

It is not a solution and I wonder how to make it right.

Solution

If MyView has correct internal layout (which depends only on own bounds), then there is not needs in external additional limitation, ie

struct MyViewRepresentable: UIViewRepresentable {
    func makeUIView(context: Context) -> UIView {
        return MyView(frame: .zero)
    }
    func updateUIView(_ uiView: UIView, context: Context) {}
}

will be exactly sized below having 400×250 frame

struct ContentView: View {
    var body: some View {
        MyViewRepresentable()
            .frame(width: 400, height: 250, alignment: .center)
    }
}

if it is not then internal MyView layout has defects.

Answered By – Asperi

Answer Checked By – Clifford M. (BugsFixing Volunteer)