[SOLVED] Python 2.7.11:Why does a function call work for one function but not for another?

Issue

I’m using Python 2.7.11 on Debian Linux.

I have two functions, one which works exactly as expected with a normal function call, and another that works well enough except for the fact that a normal function call doesn’t work on this second function; I have to put a print in front of the function in order to get it to work.

1) The first function, executing as expected with a normal function call:

def print_me(string):

    print string

    print_me("I am a string")

2)The second function, which does NOT work with a normal function call:

def fruit_color(fruit):

    fruit = fruit.lower()
    if fruit == 'apple':
        return 'red'
    elif fruit == 'banana':
        return 'yellow'
    elif fruit == 'pear':
        return 'green'
    else:
        return 'Fruit not recognized'

3) A normal function call, i.e., fruit_color(‘apple’), doesn’t work. I instead have to place print in front of the function in order to get it to work:

print fruit_color('apple')

4)Now that I’ve (hopefully) explained myself succinctly enough, I will restate my question: Why is the function call working for the print_me function but not for the fruit_color function?

Solution

print and return functions are different overall.

def print_me(string):
    print string

print_me('abc')

output:

abc

def return_me(string):
    return string

return_me('abc')

OUTPUT:

No output

Because print function in python prints the argument passed. while, return function will return the argument. So that we can use it some where else in the program if needed.

Answered By – Aravind

Answer Checked By – Mildred Charles (BugsFixing Admin)

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