[SOLVED] Is try {} without catch {} possible in JavaScript?


I have a number of functions which either return something or throw an error. In a main function, I call each of these, and would like to return the value returned by each function, or go on to the second function if the first functions throws an error.

So basically what I currently have is:

function testAll() {
    try { return func1(); } catch(e) {}
    try { return func2(); } catch(e) {} // If func1 throws error, try func2
    try { return func3(); } catch(e) {} // If func2 throws error, try func3

But actually I’d like to only try to return it (i.e. if it doesn’t throw an error). I do not need the catch block. However, code like try {} fails because it is missing an (unused) catch {} block.

I put an example on jsFiddle.

So, is there any way to have those catch blocks removed whilst achieving the same effect?


No. You have to keep them.

This actually makes sense since errors shouldn’t be silently ignored at all.

Answered By – ThiefMaster

Answer Checked By – Robin (BugsFixing Admin)

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