[SOLVED] is there a way to declare a variable with the value of a function which takes this declaring variable as a parameter?


i am wondering is there some syntax in Kotlin for declaring a variable which will be equal to a function which takes several parameters 1 of which is said variable?

class Player(var deck: MutableList<String> = Deck().deck) {

var playerHand = Deck().deal(deck, playerHand, 6)


class Deck {

var deck = mutableListOf<String>()

fun deal( from: MutableList<String>, to: MutableList<String>, num: Int ){
        var temp = from.slice(0 .. num).toMutableList()

So i basically want to transfer N amount of cards from a deck inside a Deck class to a variable playerHand in Player class. I know there are numerous other ways of doing it, i just wanted to know is there a way to create a var and assign a value to it using a function that takes that var as a parameter..


I stared at your code for a while and finally realized what you’re asking, I think: You want playerHand to be a MutableList whose initial values come from calling Deck().deal(). Like @broot says in the comment, the standard way to do this is to use also. I’m also assuming it’s some kind of typo that you are instantiating a new Deck instance to deal from, when you already have a deck property in your class. However, that property should probably be a Deck instance directly so you still have access to the Deck functionality that goes with it.

You might consider making your Deck class implement MutableList using a delegate to simplify how it is referenced and used. Now you can directly use existing MutableList functions like shuffle() directly on your Deck instance. And I would use LinkedList specifically as the delegate because it is more efficient than the default returned by mutableListOf at removing values from the top.

I would also make the deal function simply a dealTo function because it should be assumed a Deck is only going to deal from itself.

Putting that all together:

class Player(var deck: Deck = Deck()) {

    val playerHand = mutableListOf<String>().also {
        deck.dealTo(it, 6)


class Deck: MutableList<String> by LinkedList<String>() {

    fun dealTo(to: MutableList<String>, num: Int) {
        repeat(num) {
            to += removeFirst()

Answered By – Tenfour04

Answer Checked By – Robin (BugsFixing Admin)

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