[SOLVED] Is numpy.random.choice with replacement equivalent to multinomial sampling for a single trial?

Issue

I understand that strictly on concept, they are different. But in a single trial (or experiment) for numpy.random.multinomial, is it sampling the same way as numpy.random.choice though giving a different view of the output?

For example:

>> np.random.choice(6, size=6, replace=True, p=[1/6.]*6)
>> array([2, 0, 4, 2, 5, 4])

Output gives the identity of what was picked in the array [0,1,2,3,4,5]

and

>> np.random.multinomial(1, [1/6.]*6, size=6)
>> array([[0, 0, 1, 0, 0, 0],
          [0, 0, 0, 0, 0, 1],
          [0, 0, 0, 1, 0, 0],
          [0, 0, 0, 1, 0, 0],
          [0, 0, 0, 0, 1, 0],
          [1, 0, 0, 0, 0, 0]])

Output gives the number of times each choice was picked, but since it was limited to 1 trial, it can also be summarized as [2,5,3,3,4,1] from choices [0,1,2,3,4,5]

Solution

Yes, they are effectively the same.

Answered By – Robert Kern

Answer Checked By – Mildred Charles (BugsFixing Admin)

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