Issue
#include<stdio.h>
int main()
{
int i;
string A[]={"Ahmet", "Mehmet", "Bulent", "Fuat"};
for(i=0;i<=3;i++){
printf("%s",A[i]);
}
return 0;
}
How can i see my array’s elements as output?
Compiler says “‘string’ undeclared”.
Solution
This way:
char *A[] = {"Ahmet", "Mehmet", "Bülent", "Fuat"};
A
is an array of pointers to char
.
Answered By – ouah
Answer Checked By – Senaida (BugsFixing Volunteer)