[SOLVED] Elements of list in terms of array indices using Python


How do I write elements of list B in terms of array indices of A? The desired output is attached.

import numpy as np
A = np.array([[1,2,3],[4,5,6],[7,8,9]])
B = [1,5,6]

The desired output is

B=[A[0,0], A[1,1], A[1,2]]


You could use numpy.isin to see if the elements in B exist in A; then use numpy.where to find the indexes of the elements that exist. Since the indexes are separated by axes, you could finally, you could unpack and zip them to get the desired outcome:

out = list(zip(*np.where(np.isin(A, B))))

For A=np.array([[1,2,3],[4,5,6],[7,8,9]]) and B=[1,5,6,7], the output:

[(0, 0), (1, 1), (1, 2), (2, 0)]

Answered By – enke

Answer Checked By – Katrina (BugsFixing Volunteer)

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