Say the character which we want to check if it appears consecutively in a string
s is the dot
'test.2.1' does not have consecutive dots, whereas
'test..2.2a...' has consecutive dots. In fact, for the second example, we should not even bother with checking the rest of the string after the first occurence of the consecutive dots.
I have come up with the following simple method:
def consecutive_dots(s): count = 0 for c in data: if c == '.': count += 1 if count == 2: return True else: count = 0 return False
I was wondering if the above is the most ‘pythonic’ and efficient way to achieve this goal.
You can just use
in to check if two consecutive dots (that is, the string
"..") appear in the string
def consecutive_dots(s): return '..' in s
Answered By – Aziz
Answer Checked By – Marilyn (BugsFixing Volunteer)