# [SOLVED] Easy way of finding decimal places

## Issue

Is there an easy way or integrated function to find out the decimal places of a floating point number?

The number is parsed from a string, so one way is to count the digits after the ‘.’ sign, but that looks quite clumsy to me. Is there a possibility to get the information needed out of a `float` or `Decimal` object?

SOLUTION (one of them, of course 🙂 )

I chose to use the python decimal.Decimal class to help me with my problem:

``````e = abs(Decimal(string_value).as_tuple().exponent)
``````

NOTE: this only works when the parameter from which the Decimal is constructed is a string and not a float (which would lead to floating point inaccuracies).

Thanks a lot for all other contributions.

## Solution

To repeat what others have said (because I had already typed it out!), I’m not even sure such a value would be meaningful in the case of a floating point number, because of the difference between the decimal and binary representation; often a number representable by a finite number of decimal digits will have only an infinite-digit representation in binary.

In the case of a `decimal.Decimal` object, you can retrieve the exponent using the `as_tuple` method, which returns a namedtuple with `sign`, `digits`, and `exponent` attributes:

``````>>> d = decimal.Decimal('56.4325')
>>> d.as_tuple().exponent
-4
>>> d = decimal.Decimal('56.43256436')
>>> d.as_tuple().exponent
-8
``````

The negation of the exponent is the number of digits after the decimal point, unless the exponent is greater than `0`.