Issue
According to http://www.faqs.org/docs/diveintopython/fileinfo_private.html:
Like most languages, Python has the
concept of private elements:
- Private
functions, which can’t be called from
outside their module
However, if I define two files:
#a.py
__num=1
and:
#b.py
import a
print a.__num
when i run b.py it prints out 1 without giving any exception. Is diveintopython wrong, or did I misunderstand something? And is there some way to do define a module’s function as private?
Solution
In Python, “privacy” depends on “consenting adults'” levels of agreement – you can’t force it (any more than you can in real life;-). A single leading underscore means you’re not supposed to access it “from the outside” — two leading underscores (w/o trailing underscores) carry the message even more forcefully… but, in the end, it still depends on social convention and consensus: Python’s introspection is forceful enough that you can’t handcuff every other programmer in the world to respect your wishes.
((Btw, though it’s a closely held secret, much the same holds for C++: with most compilers, a simple #define private public line before #includeing your .h file is all it takes for wily coders to make hash of your “privacy”…!-))
Answered By – Alex Martelli
Answer Checked By – Terry (BugsFixing Volunteer)