# [SOLVED] Create a function that calculate the sum of odd and even values of a list and store the result within a tuple

## Issue

I am trying to solve this function.
I have to create a tuple with the sum of the even and odd numbers of this list.
So the output should be (9,12) but my function doesn’t work.
I do have to use a function

``````number_list = [1, 2, 3, 4, 5, 6]

def calculate_odd_even(odd_number, even_number):
odd_number = 0
even_number = 0
t1 = tuple()
for i in number_list:
if i % 2 == 0:
even_number = even_number + number_list[i]
t1.append(i)

else:
odd_number = odd_number + number_list[i]
t1.append(i)

return odd_number
return even_number

my_tuple = calculate_odd_even(odd_number, even_number)
``````

## Solution

You need some changes in your code:

1. No need for function arguments in this case.

• `def calculate_odd_even(odd_number, even_number)`:
• +`def calculate_odd_even()`:
2. You iterating over the elements of list, not indices.So there is no need to use `number_list[i]`, just `i` will do the
job.

• `even_number = even_number + number_list[i]`
• `odd_number = odd_number + number_list[i]`
• `even_number = even_number + i`
• `odd_number = odd_number + i`
3. Second `retrun` wont be reached ever.So instead, return a tuple.

• ``````     return odd_number
retrun even_number # Wont be reached
``````
• `return (odd_number, even_number) # currect way`

# Final code

``````number_list = [1, 2, 3, 4, 5, 6]

def calculate_odd_even():
odd_number = 0
even_number = 0
for i in number_list:
if i % 2 == 0:
even_number = even_number + i
else:
odd_number = odd_number + i

return (odd_number, even_number)

my_tuple = calculate_odd_even()
print(my_tuple) # prints (9, 12)
``````