# [SOLVED] Coursera issue for me

## Issue

The fractional_part function divides the numerator by the denominator, and returns just the fractional part (a number between 0 and 1). Complete the body of the function so that it returns the right number.
Note: Since division by 0 produces an error, if the denominator is 0, the function should return 0 instead of attempting the division.

here is my code:

``````def fractional_part(numerator, denominator):
# Operate with numerator and denominator to
# keep just the fractional part of the quotient
if denominator == 0 or numerator == 0:
print("0")
else:
fraction = numerator / denominator
while fraction > 1:
fraction1 = fraction - 1
return fraction1

print(fractional_part(5, 5)) # Should be 0
print(fractional_part(5, 4)) # Should be 0.25
print(fractional_part(5, 3)) # Should be 0.66...
print(fractional_part(5, 2)) # Should be 0.5
print(fractional_part(5, 0)) # Should be 0
print(fractional_part(0, 5)) # Should be 0
``````

This is my output:

UnboundLocalError: local variable ‘fraction1’ referenced before assignment

## Solution

If you change `fraction1` to `fraction` you will solve the problem that `fraction1` is not defined. Then you need to add `fraction = 0` after the first `if` to solve if `denominator` or `numerator` is `0`

``````def fractional_part(numerator, denominator):
# Operate with numerator and denominator to
# keep just the fractional part of the quotient
if denominator == 0 or numerator == 0:
fraction = 0 #to solve if denominator or numerator is 0
print("0")
else:
fraction = numerator / denominator
while fraction > 1:
fraction = fraction - 1
return fraction
``````