Issue
How can I convert a String "Hello"
to an Array ["H","e","l","l","o"]
in Swift?
In Objective-C I have used this:
NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
NSString *ichar = [NSString stringWithFormat:@"%c", [myString characterAtIndex:i]];
[characters addObject:ichar];
}
Solution
It is even easier in Swift:
let string : String = "Hello 🐶🐮 🇩🇪"
let characters = Array(string)
println(characters)
// [H, e, l, l, o, , 🐶, 🐮, , 🇩🇪]
This uses the facts that
- an
Array
can be created from aSequenceType
, and String
conforms to theSequenceType
protocol, and its sequence generator
enumerates the characters.
And since Swift strings have full support for Unicode, this works even with characters
outside of the “Basic Multilingual Plane” (such as 🐶) and with extended grapheme
clusters (such as 🇩🇪, which is actually composed of two Unicode scalars).
Update: As of Swift 2, String
does no longer conform to
SequenceType
, but the characters
property provides a sequence of the
Unicode characters:
let string = "Hello 🐶🐮 🇩🇪"
let characters = Array(string.characters)
print(characters)
This works in Swift 3 as well.
Update: As of Swift 4, String
is (again) a collection of its
Character
s:
let string = "Hello 🐶🐮 🇩🇪"
let characters = Array(string)
print(characters)
// ["H", "e", "l", "l", "o", " ", "🐶", "🐮", " ", "🇩🇪"]
Answered By – Martin R
Answer Checked By – Mary Flores (BugsFixing Volunteer)