Issue
Is a function without a storage class specified in its declaration and definition :
void func(void); // declaration
void func(void) { // implementation
}
be equivalent to the function with extern storage class in its declaration and definition? :
extern void func(void); // declaration
extern void func(void) { // implementation
}
Solution
From the C Standard (6.2.2 Linkages of identifiers)
5 If the declaration of an identifier for a function has no
storage-class specifier, its linkage is determined exactly as if it
were declared with the storage-class specifier extern. If the
declaration of an identifier for an object has file scope and no
storage-class specifier, its linkage is external.
Answered By – Vlad from Moscow
Answer Checked By – Cary Denson (BugsFixing Admin)